Добавил:
Karsky
Опубликованный материал нарушает ваши авторские права? Сообщите нам.
Вуз:
Предмет:
Файл:экза мен / экзамен / 2.Водныя рэсурсы Беларусі і спецыфіка іх выкарыстання / 2.3.Размеркаванне сцёку па порам года
.txt яю!FQ: ?0 BM@KB>@KV 5;0@CAV 7<O=O5FF0 C HK@>B=K< =0?@0<:C @070< A0 7<5=09 :;V<0BKG=KE C<>^.
;O 1>;LH0AFV @M: 0A=>^=0O G0AB:0 @0G=>30 AFQ:C ?>@0E>47VFL 2OA=>9 C G0A B0O==O A=53C ( @KA. 2 . 1 ) . 03MB0<C E0@0:B0@ 2OA=02>30 @072>447O ( O3> ?@0FO3;0AFL, 01 Q<, 4>;O C 30402K< AFQ:C) C 7=0G=09 <5@K 2K7=0G05 0A01;V20AFV @07<5@:020==O AFQ:C =0 ?@0FO3C 3>40. !O@M4=OO 25;VGV=O AFQ:C 2OA=>9 20305FF0 04 4 0 40 1 7 0 <<. MB0 A:;0405 04 3 0 40 7 0 % 30402>30 AFQ:C. 5;VGK=O 25A=02>30 ?0^=02>447O <05 A205 0A01;V20AFV O: C HK@>B=K< =0?@0<:C, B0: V ?0 10A59=0< 0A=>^=KE @M: 5;0@CAV.
5A=02>5 @072>4475 7<O=O5FF0 =V7:09 ;5B=O9 <560==N. A=>^=09 :@K=VF09 6K^;5==O ^ <560=L 7 O^;ONFF0 3@C=B>2KO 2>4K. 5B=5- 0A5==OO <560=L G0AB0 ?0@CH05FF0 4064602K<V ?02>4:0<V. 5:0B>@KO <0;KO @M:V ?0^4=Q209 G0AB:V 5;0@CAV C <560=L ?5@0AKE0NFL. >;O ;5B=5- 0A5==O30 AFQ:C A:;0405 04 1 8 40 4 3 % 30402>9 25;VGK=V.
V<>9 AFQ: A?0G0B:C ?0=V605FF0, 0 70BK< ?0ABC?>20 ?02O;VG205FF0. # ?5@KO4 7V<>2KE 04;V30^ G0AB0 =07V@0NFF0 7V<>2KO ?02>4:V. # AC@>2KO 7V<K <0;KO @M:V G0AB0 ?5@0<O@70NL V AFQ: A?K=O5FF0. !O@M4=V AFQ: 70 7V<C 7<O=O5FF0 04 4 40 2 5 % V ?0<O=H055FF0 7 ?>^=0GK =0 ?>^475=L.
0 0A0=>25 0=0;V70 3V4@>3@0D0^ AFQ:C =0 5;0@CAV 2K47O;ONFF0 <56K ?0G0B:C V :0=F0 3V4@0;03VG=KE ?>@0^ 3>40: 2OA=K ( A0:02V: B@025=L) , ;5B0 - 2>A5=L ( GM@25=L ;VAB0?04) , 3V4@0;03VG=0O 7V<0 ( A=560=L ;NBK) . MB0 03C;L=KO BM@<V=K 3V4@0;03VG=KE ?>@ 3>40. 4=0: 2K:;NGM==5 A:;040NFL @0:0 @K?OFL V O5 ;52KO ?@KB>:V >1@K: V /A5;L40, 4;O O:VE 2K47O;O5FF0 2OA=0 ?5@H0O ?0;02V=0 ;5B0 ( A0:02V: GM@25=L) V 4@C30O ?0;02V=0 ;5B0 2>A5=L ( ;V?5=L ;VAB0?04) . 0 4@C3V< ?@KB>:0< @. @K?OFV 25A=02>5 @072>4475 A?0405 C 0A=>^=K< C <0V. "<C 4;O VE 3V4@0;03VG=KO ?>@K 3>40 V VE BM@<V=K AC?040NFL 7 BM@<V=0<V 4;O 1>;LH0AFV @M: 5;0@CAV.
;O ?@0:BK:V <05 7=0GM==5 ?@5KO4K 3>40, C O:VO AFQ: @M: 1K205 =09<5=LHK, HB> 25;L<V 01<O6>^205 ( ;V<VFV@C5) A?06K20==5 204K C 30A?040@GKE <MB0E. KE>47OGK 7 2>4=0AFV @M: 4;O CAQ9 BM@KB>@KV 5;0@CAV 70 01<O6>^20NGK ?5@KO4 ?@K9<0NFF0 4725 <0;02>4=KO ?0@K ( ;5B0- 2>A5=L, 7V<0) . 0 01<O6>^20NGCN ?0@C 3>40 ?@K9<05FF0 ;5B0- 2>A5=L, FV 7V<0. MB0 70;56KFL 04 B03>, O:VO 7 3MBKE ?>@0^ 3>40 7 O^;ONFF0 ?5@0206=0 <0;02>4=K<V 70 C25AL ?5@KO4 =07V@0==O^. ;O 1>;LH0AFV AFQ:02KE 3V4@0;03VG=KE ?0AB>^ 3V4@0;03VG=KO @04K =07V@0==O^A:;040NFL =5 <5=H 5 0 304>^.
KAC=0: 2 . 2 04;NAB@>^205 @07<5@:020==5 <V=V<0;L=030 AFQ:C ?0 BM@KB>@KV 5;0@CAV. 0V<5=HKO 7=0GM==V <V=V<0;L=030 AFQ:C ?@KE>47OFF0 =0 ?0^4=Q2CN G0AB:C BM@KB>@KV. # 04?0254=0AFV 7 7<O=5==5< ?0475<=030 6K^;5==O @M: 7=0E>47VFF0 V @07<5@:020==5 <V=V<0;L=030 AFQ:C @M: ?0 BM@KB>@KV. !O@M4=VO <=030;5B=VO <V=V<C<K ACB0G=030 AFQ:C C ;5B=V ?5@KO4 7<O=ONFF0 04 0 , 1 0 40 4 , 1 6 ;/ A :<2 , 0 C 7V<>2 0 , 1 9 4 , 1 2 ;/ A :<2 . # 0A>1=KO 304K AFQ: 7=0G=0 04@>7=V205FF0 04 3MBK 25;VGK=L, 0 =0 0A>1=KE CG0A:0E <0;KE @M: Q= C2>3C;5 7=V:05. !0<KO =V7:VO <>4C;V AFQ:C V 2K?04:V ?5@0AKE0==O V ?@0<O@70==O E0@0:BM@=K @M:0< 0;5AAO. V7:V AFQ: @M =07V@05FF0 B0:A0<0 =0 CAE>475 V ?0^=>G=K< 70E0475 ( 10A59= @. 7VA=K) . 091>;LH 2KA>:VO 7=0GM==V <V=V<0;L=030 AFQ:C =07V@0NFF0 =0 @M:0E, O:VO ?@0FO:0NFL ?0 V=A:09 V H<O=A:09 C72KHH0<, 0 B0:A0<0 =0 ?0^=>G=K< CAE>475 C 10A5=9 @. 0E>4=O9 72V=K.
;O @M: 5;0@CAV E0@0:BM@=0 =0O^=0AFL 472NE ?5@KO40^ =V7:030 AFQ:C 70 3>4 ;5B=5- 0A5==V V 7V<=V. @V 04ACB=0AFV ?02>40: ?@0FO3;0AFL ;5B=5- 0A5==530 <560==030 ?5@KO40 2KE7=0G05FF0 04 :0=F0 ?0^=02>447O 40 7 O^;5==O =0 @M:0E ;O4>2KE 7 O^. @0FO3;0AFL 7V<>209 <560=V ?@K 04ACB=0AFV ?02>40: ?@K=OB0 04 ?0G0B:C 7V<>2030 ?5@KO40 40 ?0G0B:C ?0^=02>447O. @K =0O^=0AFV ?02>40: C :0=FK 2>A5=V ?0G0B:C 7V<K 70 ?0G0B0: <560=V ?@K9<05FF0 40B0 70:0=GM==O ?02>4:V FV E20;V ?02>40:. 560=L ;VGKFF0 =5?5@0@20=09 ?@K 01 Q<5 ?02>40: =5 1>;LH 1 0 1 5 % 25;VGK=V 01 Q<0 AFQ:C 70 ?5@KO4 04 ?0G0B:C <560=V 40 :0=F0 ?02>4:V. 0A;O 2K7=0GM==O <560=V C 03C;L=K< 2K7=0G05FF0 =091>;LH <0;02>4=K O5 ?5@KO4, =0 O:V ?@KE>47VFF0 =09<5=HK ACB0G=K @0AE>;4 204K.
0:AV<0;L=K AFQ:. 5A=02>5 ?0^=02>4475 7 O^;O5FF0 E0@0:BM@=09 D0709 @M6K<0 @M:, 7O O:V ?@0E>47VFL 04 4 0 40 6 0 % 0403C;L=030 30402>30 AFQ:C. # 3MBK G0A =07V@0NFF0 =091>;LHKO @0AE>4K 204K. 5A=02>5 ?0^=02>4475 ?0GK=05FF0 =0 ?0^4=Q2K< 70E0475 C AO@M4=V< C ?0G0B:C A0:02V:0 C ?5@H09 ?0;02V=5 :@0A02V:0. # 0A>1=KO 304K BM@<V=K ?0G0B:C ?0^=02>447O 2030NFF0 C 7=0G=KE <560E, 0A01;V20 C 10A59=5 Q<0=0 V @K?OFV, 475 @0==VO 40BK CA:@KFFO =07V@0NFF0 H 4@C3>9 4M:0475 ;NB030. M:V C 10A59=5 0E>4=O9 72V=K CA:@K20NFF0 @0==O9 2OA=>9 C ?0G0B:C A0:02V:0. @0FO3;0AFL ?0^=02>447O 70;56KFL 04 25;VGK=V @0:V V 70@M3C;O20=0AFV AFQ:C. ;O @M: 10A59=0 =O?@0 ( 157 @K?OFV) , Q<0=0 AO@M4=OO ?@0FO3;0AFL ?0^=02>447O 20305FF0 04 3 0 3 5 47Q= =0 <0;KE 204071>@0E 40 8 0 9 0 47Q= =0 2O;V:VE ( @. !>6 3. ><5;L V @. =O?@> 3. MGKF0) . 0:0 @K?OFL 7=0G=0 7010;>G0=KO O5 ;5201O@M6=KO ?@KB>:V ( /A5;L40, >1@K:, &=0, VBL) <0NFL =091>;LHCN ?@0FO3;0AFL ?0^=02>447O. @0FO3;0AFL ?0^=02>447O @. @K?OFL 40AO305 1 2 0 47Q=, @. 5@0G0=CV ( ?@KB>: /A5;L4K) - :0;O 6 0 47Q=.
!O@M4=V A;>9 AFQ:C 70 ?0^=02>4475 20305FF0 ^ <560E 5 0 6 0 << =0 ?>^4=V 40 1 6 0 << =0 ?0^=>G=K< CAE>475. >;O 4064602>30 AFQ:C A:;0405 1 0 1 5 % 04 AC<0@=030. @C=B>2K AFQ: @M: O@M77V=K, V;VV 04 AC<0@=030 A:;0405 2 5 - 3 0 % , 4;O @M: =O?@>, !060, 0E>4=O9 72V=K 1 0 1 2 % .
0 0?>H=VO 5 0 1 0 0 304>^ =0 5;0@CAV =07V@0^AO HM@03 3>4 7 25;L<V 2KA>:V<V ?0^=02>447O<V. KA>:05 ?0^=02>4475 1 9 0 8 3>40 0E0?V;0 @M:V =O?@0 V 0E>4=O9 72V=K. 091>;LH05 ?0^=02>44755 7 <0:AV<0;L=K< 0E0?;5==5< BM@KB>@KV 5;0@CAV =07V@0;0AO C 1 9 3 1 3>475. 0B0AB@0DVG=05 ?0^=02>4475 C 1 9 5 8 3>475 0E0?V;0 ;5201O@M660 @. Q<0=0. 0 @K?OFV V O5 ;5201O@M6=KE ?@KB>:0E A0<05 2KA>:05 ?0^=02>4475 1K;> C 1 8 9 5 3.
;O @07;V:C 25;VGV=V AFQ:C 70 3>4 2K1V@0NFF0 =0ABC?=KO 3@040FKV 2>4=0AFV ( AFQ:C) : 25;L<V <=0302>4=K ( 701OA?5G0=0AFL 5 % ) , <=0302>4=K ( 2 5 % ) , AO@M4=V ?0 2>4=0AFV ( 5 0 % ) , <0;02>4=K ( 7 5 % ) V 25;L<V <0;02>4=K ( 9 5 % ) .
;O 1>;LH0AFV @M: 0A=>^=0O G0AB:0 @0G=>30 AFQ:C ?>@0E>47VFL 2OA=>9 C G0A B0O==O A=53C ( @KA. 2 . 1 ) . 03MB0<C E0@0:B0@ 2OA=02>30 @072>447O ( O3> ?@0FO3;0AFL, 01 Q<, 4>;O C 30402K< AFQ:C) C 7=0G=09 <5@K 2K7=0G05 0A01;V20AFV @07<5@:020==O AFQ:C =0 ?@0FO3C 3>40. !O@M4=OO 25;VGV=O AFQ:C 2OA=>9 20305FF0 04 4 0 40 1 7 0 <<. MB0 A:;0405 04 3 0 40 7 0 % 30402>30 AFQ:C. 5;VGK=O 25A=02>30 ?0^=02>447O <05 A205 0A01;V20AFV O: C HK@>B=K< =0?@0<:C, B0: V ?0 10A59=0< 0A=>^=KE @M: 5;0@CAV.
5A=02>5 @072>4475 7<O=O5FF0 =V7:09 ;5B=O9 <560==N. A=>^=09 :@K=VF09 6K^;5==O ^ <560=L 7 O^;ONFF0 3@C=B>2KO 2>4K. 5B=5- 0A5==OO <560=L G0AB0 ?0@CH05FF0 4064602K<V ?02>4:0<V. 5:0B>@KO <0;KO @M:V ?0^4=Q209 G0AB:V 5;0@CAV C <560=L ?5@0AKE0NFL. >;O ;5B=5- 0A5==O30 AFQ:C A:;0405 04 1 8 40 4 3 % 30402>9 25;VGK=V.
V<>9 AFQ: A?0G0B:C ?0=V605FF0, 0 70BK< ?0ABC?>20 ?02O;VG205FF0. # ?5@KO4 7V<>2KE 04;V30^ G0AB0 =07V@0NFF0 7V<>2KO ?02>4:V. # AC@>2KO 7V<K <0;KO @M:V G0AB0 ?5@0<O@70NL V AFQ: A?K=O5FF0. !O@M4=V AFQ: 70 7V<C 7<O=O5FF0 04 4 40 2 5 % V ?0<O=H055FF0 7 ?>^=0GK =0 ?>^475=L.
0 0A0=>25 0=0;V70 3V4@>3@0D0^ AFQ:C =0 5;0@CAV 2K47O;ONFF0 <56K ?0G0B:C V :0=F0 3V4@0;03VG=KE ?>@0^ 3>40: 2OA=K ( A0:02V: B@025=L) , ;5B0 - 2>A5=L ( GM@25=L ;VAB0?04) , 3V4@0;03VG=0O 7V<0 ( A=560=L ;NBK) . MB0 03C;L=KO BM@<V=K 3V4@0;03VG=KE ?>@ 3>40. 4=0: 2K:;NGM==5 A:;040NFL @0:0 @K?OFL V O5 ;52KO ?@KB>:V >1@K: V /A5;L40, 4;O O:VE 2K47O;O5FF0 2OA=0 ?5@H0O ?0;02V=0 ;5B0 ( A0:02V: GM@25=L) V 4@C30O ?0;02V=0 ;5B0 2>A5=L ( ;V?5=L ;VAB0?04) . 0 4@C3V< ?@KB>:0< @. @K?OFV 25A=02>5 @072>4475 A?0405 C 0A=>^=K< C <0V. "<C 4;O VE 3V4@0;03VG=KO ?>@K 3>40 V VE BM@<V=K AC?040NFL 7 BM@<V=0<V 4;O 1>;LH0AFV @M: 5;0@CAV.
;O ?@0:BK:V <05 7=0GM==5 ?@5KO4K 3>40, C O:VO AFQ: @M: 1K205 =09<5=LHK, HB> 25;L<V 01<O6>^205 ( ;V<VFV@C5) A?06K20==5 204K C 30A?040@GKE <MB0E. KE>47OGK 7 2>4=0AFV @M: 4;O CAQ9 BM@KB>@KV 5;0@CAV 70 01<O6>^20NGK ?5@KO4 ?@K9<0NFF0 4725 <0;02>4=KO ?0@K ( ;5B0- 2>A5=L, 7V<0) . 0 01<O6>^20NGCN ?0@C 3>40 ?@K9<05FF0 ;5B0- 2>A5=L, FV 7V<0. MB0 70;56KFL 04 B03>, O:VO 7 3MBKE ?>@0^ 3>40 7 O^;ONFF0 ?5@0206=0 <0;02>4=K<V 70 C25AL ?5@KO4 =07V@0==O^. ;O 1>;LH0AFV AFQ:02KE 3V4@0;03VG=KE ?0AB>^ 3V4@0;03VG=KO @04K =07V@0==O^A:;040NFL =5 <5=H 5 0 304>^.
KAC=0: 2 . 2 04;NAB@>^205 @07<5@:020==5 <V=V<0;L=030 AFQ:C ?0 BM@KB>@KV 5;0@CAV. 0V<5=HKO 7=0GM==V <V=V<0;L=030 AFQ:C ?@KE>47OFF0 =0 ?0^4=Q2CN G0AB:C BM@KB>@KV. # 04?0254=0AFV 7 7<O=5==5< ?0475<=030 6K^;5==O @M: 7=0E>47VFF0 V @07<5@:020==5 <V=V<0;L=030 AFQ:C @M: ?0 BM@KB>@KV. !O@M4=VO <=030;5B=VO <V=V<C<K ACB0G=030 AFQ:C C ;5B=V ?5@KO4 7<O=ONFF0 04 0 , 1 0 40 4 , 1 6 ;/ A :<2 , 0 C 7V<>2 0 , 1 9 4 , 1 2 ;/ A :<2 . # 0A>1=KO 304K AFQ: 7=0G=0 04@>7=V205FF0 04 3MBK 25;VGK=L, 0 =0 0A>1=KE CG0A:0E <0;KE @M: Q= C2>3C;5 7=V:05. !0<KO =V7:VO <>4C;V AFQ:C V 2K?04:V ?5@0AKE0==O V ?@0<O@70==O E0@0:BM@=K @M:0< 0;5AAO. V7:V AFQ: @M =07V@05FF0 B0:A0<0 =0 CAE>475 V ?0^=>G=K< 70E0475 ( 10A59= @. 7VA=K) . 091>;LH 2KA>:VO 7=0GM==V <V=V<0;L=030 AFQ:C =07V@0NFF0 =0 @M:0E, O:VO ?@0FO:0NFL ?0 V=A:09 V H<O=A:09 C72KHH0<, 0 B0:A0<0 =0 ?0^=>G=K< CAE>475 C 10A5=9 @. 0E>4=O9 72V=K.
;O @M: 5;0@CAV E0@0:BM@=0 =0O^=0AFL 472NE ?5@KO40^ =V7:030 AFQ:C 70 3>4 ;5B=5- 0A5==V V 7V<=V. @V 04ACB=0AFV ?02>40: ?@0FO3;0AFL ;5B=5- 0A5==530 <560==030 ?5@KO40 2KE7=0G05FF0 04 :0=F0 ?0^=02>447O 40 7 O^;5==O =0 @M:0E ;O4>2KE 7 O^. @0FO3;0AFL 7V<>209 <560=V ?@K 04ACB=0AFV ?02>40: ?@K=OB0 04 ?0G0B:C 7V<>2030 ?5@KO40 40 ?0G0B:C ?0^=02>447O. @K =0O^=0AFV ?02>40: C :0=FK 2>A5=V ?0G0B:C 7V<K 70 ?0G0B0: <560=V ?@K9<05FF0 40B0 70:0=GM==O ?02>4:V FV E20;V ?02>40:. 560=L ;VGKFF0 =5?5@0@20=09 ?@K 01 Q<5 ?02>40: =5 1>;LH 1 0 1 5 % 25;VGK=V 01 Q<0 AFQ:C 70 ?5@KO4 04 ?0G0B:C <560=V 40 :0=F0 ?02>4:V. 0A;O 2K7=0GM==O <560=V C 03C;L=K< 2K7=0G05FF0 =091>;LH <0;02>4=K O5 ?5@KO4, =0 O:V ?@KE>47VFF0 =09<5=HK ACB0G=K @0AE>;4 204K.
0:AV<0;L=K AFQ:. 5A=02>5 ?0^=02>4475 7 O^;O5FF0 E0@0:BM@=09 D0709 @M6K<0 @M:, 7O O:V ?@0E>47VFL 04 4 0 40 6 0 % 0403C;L=030 30402>30 AFQ:C. # 3MBK G0A =07V@0NFF0 =091>;LHKO @0AE>4K 204K. 5A=02>5 ?0^=02>4475 ?0GK=05FF0 =0 ?0^4=Q2K< 70E0475 C AO@M4=V< C ?0G0B:C A0:02V:0 C ?5@H09 ?0;02V=5 :@0A02V:0. # 0A>1=KO 304K BM@<V=K ?0G0B:C ?0^=02>447O 2030NFF0 C 7=0G=KE <560E, 0A01;V20 C 10A59=5 Q<0=0 V @K?OFV, 475 @0==VO 40BK CA:@KFFO =07V@0NFF0 H 4@C3>9 4M:0475 ;NB030. M:V C 10A59=5 0E>4=O9 72V=K CA:@K20NFF0 @0==O9 2OA=>9 C ?0G0B:C A0:02V:0. @0FO3;0AFL ?0^=02>447O 70;56KFL 04 25;VGK=V @0:V V 70@M3C;O20=0AFV AFQ:C. ;O @M: 10A59=0 =O?@0 ( 157 @K?OFV) , Q<0=0 AO@M4=OO ?@0FO3;0AFL ?0^=02>447O 20305FF0 04 3 0 3 5 47Q= =0 <0;KE 204071>@0E 40 8 0 9 0 47Q= =0 2O;V:VE ( @. !>6 3. ><5;L V @. =O?@> 3. MGKF0) . 0:0 @K?OFL 7=0G=0 7010;>G0=KO O5 ;5201O@M6=KO ?@KB>:V ( /A5;L40, >1@K:, &=0, VBL) <0NFL =091>;LHCN ?@0FO3;0AFL ?0^=02>447O. @0FO3;0AFL ?0^=02>447O @. @K?OFL 40AO305 1 2 0 47Q=, @. 5@0G0=CV ( ?@KB>: /A5;L4K) - :0;O 6 0 47Q=.
!O@M4=V A;>9 AFQ:C 70 ?0^=02>4475 20305FF0 ^ <560E 5 0 6 0 << =0 ?>^4=V 40 1 6 0 << =0 ?0^=>G=K< CAE>475. >;O 4064602>30 AFQ:C A:;0405 1 0 1 5 % 04 AC<0@=030. @C=B>2K AFQ: @M: O@M77V=K, V;VV 04 AC<0@=030 A:;0405 2 5 - 3 0 % , 4;O @M: =O?@>, !060, 0E>4=O9 72V=K 1 0 1 2 % .
0 0?>H=VO 5 0 1 0 0 304>^ =0 5;0@CAV =07V@0^AO HM@03 3>4 7 25;L<V 2KA>:V<V ?0^=02>447O<V. KA>:05 ?0^=02>4475 1 9 0 8 3>40 0E0?V;0 @M:V =O?@0 V 0E>4=O9 72V=K. 091>;LH05 ?0^=02>44755 7 <0:AV<0;L=K< 0E0?;5==5< BM@KB>@KV 5;0@CAV =07V@0;0AO C 1 9 3 1 3>475. 0B0AB@0DVG=05 ?0^=02>4475 C 1 9 5 8 3>475 0E0?V;0 ;5201O@M660 @. Q<0=0. 0 @K?OFV V O5 ;5201O@M6=KE ?@KB>:0E A0<05 2KA>:05 ?0^=02>4475 1K;> C 1 8 9 5 3.
;O @07;V:C 25;VGV=V AFQ:C 70 3>4 2K1V@0NFF0 =0ABC?=KO 3@040FKV 2>4=0AFV ( AFQ:C) : 25;L<V <=0302>4=K ( 701OA?5G0=0AFL 5 % ) , <=0302>4=K ( 2 5 % ) , AO@M4=V ?0 2>4=0AFV ( 5 0 % ) , <0;02>4=K ( 7 5 % ) V 25;L<V <0;02>4=K ( 9 5 % ) .
Соседние файлы в папке 2.Водныя рэсурсы Беларусі і спецыфіка іх выкарыстання