экза мен / экзамен / 10. Кар’ерныя вадаёмы / 10.2. Рэкультывацыя кар'ераў

яю10.2. M:C;LBK20FKO :0@'5@0^



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

@C3V< H;OE0< @M:C;LBK20FKV, O:V 04@>7=V205FF0 A2059 M:0;03VG=0AFN V ?@0AB0B>9, 7'O^;O5FF0 70E020==5 :0@'5@0^ V 70?0^=5==5 VE 204>9, 3MB0 7=0GKFL CB20@M==5 =0 <5AFK 04?@0F020=KE @04>2VHG0^ :0@'5@=KE 20405<0^ @07=0<MB02030 ?@K7=0GM==O. 0@07 C @MA?C1;VFK :0;O 10 % B0:VE @0A?@0F>20: AB0;V 01'5:B0<V 2>4030A?040@G09 @M:C;LBK20FKV.

0@'5@=KO 20405<K  3MB0 @C:0B2>@=KO ?@K@>4=0-0=B@0?035==KO 2>4=KO M:0AVABM<K, AB0=0^;5==5 V DC=:FKO=020==5 O:VE OHGM 40A:0=0;0 =5 2K2CG0=K.

0@'5@=KO 20405<K 5;0@CAV 2K:0@KAB>^20NFF0 ^ 30A?040@GKE V MABMBKG=KE V=B0@MA0E 3@0<04AB20 ^ O:0AFV:

1)A060;0: 4;O @K10@072O475==O;

2)2040AE>2VHG0^;

3)20405<0^ 4;O 04?0GK=:C V A?>@BC (@M:@M0FKV);

4)4;O <OAF>2KE ?0B@M1 (0@0HM==5);

5)04AB>9=V:0^ 4;O 2>40^ 7 ?@0<KA;>2KE V A5;LA:030A?040@GKE ?@04?@K5<AB20^.

50M:0;03VG=05 701OA?OGM==5 2>4=030A?040@G09 @M:C;LBK20FKV 06KFFO^;O5FFM ?0MB0?=0 (%><VG ..,2001):

- @0A?@0F>^:0 BME=V:0-M:0=0<VG=030 013@C=B020==O 0A205==O @04>2VHG0 V O3> @M:C;LBK20FKV;

- :0@M:FKO V 4MB0;V70FKO ?@05:B0 @M:C;LBK20FKV :0@ 5@=0-0420;L=030 :><?;5:AC, O:V 0B@K<;V205FF0 =0 <5AFK 04?@0F020=030 @04>2VHG0;

- :V@020==5 DC=:FKO=V@020==5< AD0@<V@020=030 2040Q<0 :0@ 5@=030 BK?C.

0 ?5@HK< MB0?5 2K7=0G05FF0 <03GK<0AFL V <MB073>4=0AFL AB20@M==O 2040Q<0. 0A;O4>^=0 2K7=0G0NFF0 3V4@0;03VG=KO, 3V4@0350;03VG=KO, 350<0@D0;03VG=KO, 3>@=0-350;03VG=KO, ;0=4H0DB=KO ^<>2K 2>4=030A?040@G09 @M:C;LBK20FKV.  =0?@0<0: VE 30A?040@G030 2K:0@KAB0==O. FM=L205FF0 :@K=VFK 6K^;5==O 1C4CG030 2040Q<0, VE 40AB0B:>20AFL 4;O D0@<V@020==O 0?BK<0;L=030 01 Q<0 2>4=09 <0AK V 701OA?OGM==O =04759=030 204001<5=C.  C;V:0< BK?0 @04>2VHG0, BME=0;>3VV O3> @0A?@0F>^:V, 2K7=0G0NFF0 ?0@0<5B@K 1C4CG030 2040Q<0.

0 2K=V:0< 0FM=:V <03GK<KE <0@D0<5B@KG=KE ?0:07GK:0^ 2K7=0G05FF0 ?5@A?5:BK2K D0@<V@020==O 1V0;03VG=030 BK?C 2040Q<0, O3> ?@04C:FK9=KO <03GK<0AFV V 04?0254=0AFL 0?BK<0;L=K< AC04=>AV=0< ?0<V6 V<V. 4=0G0A>20 ?@04C3;54620NFF0 <5@0?@K5<AB2K ?0 0@30=V70FKVV 204071>@0 1C4CG030 2040Q<C, 350M:0;03VG=09 O3> @M:C;LBK20FKV. %0@0:B0@KABK:V 2040Q<0 V 204071>@0 7 O^;ONFF0 0A=>209 4;O ?;0=V@C5<030 O3>2K:0@KAB0==O.

@C3V MB0? C:;NG05 350M:0;03VG=K 0=0;V7 A0<>30 :0@ 5@0 O: 04<>^=CN D>@<C @M;L5D0 V 4=> 1C4CG030 2040Q<0. 0 3MBK< MB0?C C40:;04=ONFF0 <56K 204071>@0, ?0<5@K ?@K1O@M6=KE 2>4<5;59, 15@03020O ;V=VO, ?;O6, <5@0?@K5<AB2K ?0 ?;0=V@>^FK 4=0 2040Q<0. ;0=CNFF0 <5@0?@K5<AB2K ?0 1VO;03VG=09 @M:C;LBK20FKV <0;>30 204071>@0 V 3V4@01VO;03VG=09 @M:C;LBK20FKV ?@K1O@M6=09 <5;:02>4=09 7>=K, ;V:2V40FKO ?0BM=FKO;L=KE :@K=VF 701@C4620==O.

"@MFV MB0? C:;NG05 <0=VB>@K=3 70 AB0=0< =>2KE 3V4@0M:0AVABM< V :V@020==5 VE DC=:FKO=V@020==5< 7 <MB09 0FM=:V 04?0254=0AFV =07V@05<KE VE ;V<=0;03VG=KE ?0:07GK:0^ @07;V:>2K< V V A0=VB0@=0-3V3V5=VG=K< ?0@0<5B@0<.