#include <iostream>
#include <iomanip>
#include <math.h>
using namespace std;
int main()
{
double x, y;
cout.precision(5);
cout << setw(10) << "x=" << "\t" << setw(10) << "y=" << endl;
for (x = 0.5; x <= 5; x += 2.1)
{
y = 2 * exp(4 * x);
cout << setw(10) << x << "\t" << setw(10) << y << endl;
}
return 0;
}
#include <iostream>
#include <iomanip>
#include <math.h>
using namespace std;
int main()
{
double x, y;
cout.precision(5);
cout << setw(10) << "x=" << "\t" << setw(10) << "y=" << endl;
x = 0.5;
while (x<=5)
{
y = 2 * exp(4 * x);
cout << setw(10) << x << "\t" << setw(10) << y << endl;
x += 2.1;
}
return 0;
}
#include <iostream>
#include <iomanip>
#include <math.h>
using namespace std;
int main()
{
double x, y;
cout.precision(5);
cout << setw(10) << "x=" << "\t" << setw(10) << "y=" << endl;
x = 0.5;
do
{
y = 2 * exp(4 * x);
cout << setw(10) << x << "\t" << setw(10) << y << endl;
x += 2.1;
} while (x <= 5);
return 0;
}
Задание 2
#include <iostream>
#include <iomanip>
#include <math.h>
using namespace std;
int main()
{
double x, y, z,s, p, min, max;
min = 10000;
max = 10000;
s = 0;
p = 1;
cout.precision(5);
cout << setw(10) << "x=" << "\t" << setw(10) << "y=" << "\t" << setw(10) << "z=" << endl;
for (x = 2; x <= 3.2; x += 0.7)
for (y = 0.5; y <= 1; y += 0.22)
{
if ((x / y) < 1)
z = (pow(y, 1. / 3)*(4 * pow(x, 2) + 1)) / (3 * pow(cos(fabs(x - y)), 2));
else
z = (tan(x*y) + 2.6) / (sqrt(sin(x)));
cout << setw(10) << x << "\t" << setw(10) << y << "\t" << setw(10) << z << endl;
if (min < z)
min = z;
if (max > 2)
max = z;
s = s + z;
p = p*z;
}
cout << "s=" << s << endl;
cout << "p=" << p << endl;
return 0;
}
}
Задание 3
#include <iostream>
#include <iomanip>
#include <math.h>
using namespace std;
int main()
{
double x, y, a, b, z;
cout.precision(5);
cout << setw(10) << "x=" << "\t" << setw(10) << "y=" << "\t" << setw(10) << "z=" << endl;
x = 2.5;
while (x<=5)
{
y = 3;
while (y<=3.5)
{
a = log(x + (x / y));
b = (pow(y, 1. / 3)*(4 * pow(x, 2) + 1)) / (3 * pow(cos(fabs(x - y)), 2));
if (a < b)
z = a;
else
z = b;
cout << setw(10) << x << "\t" << setw(10) << y << "\t" << setw(10) << z << endl;
y = y + 0.25;
}
x = x + 2;
}
return 0;
}
