Практика.

Для функций, заданных по Вашему варианту, построить таблицы истинности, аналитическое выражение в КФ и ДФ и попытаться его минимизировать. Записать инверсную функцию.

Варианты:

1. f (1,2,3,4) = 1 ; f (2,4,5,6,7) = 1 ; f (1,2,3,8,13,14,15) = 1;

2. f (1,2,4,5) = 1 ; f (3,4,5,6,7) = 1 ; f (1,2,4,8,12,14,15) = 1;

3. f (1,2,5,6) = 1 ; f (1,3,5,6,7) = 1 ; f (1,2,5,7,13,14,15) = 1;

4. f (1,2,6,7) = 1 ; f (1,3,4,6,7) = 1 ; f (1,2,4,9,11,12,15) = 1;

5. f (0,2,4,6) = 1 ; f (1,2,4,5,7) = 1 ; f (0,3,5,10,12,13,14) = 1;

6. f (0,3,5,6) = 1 ; f (0,1,2,6,7) = 1 ; f (1,2,3,5,7,10,14) = 1;

7. f (1,2,5,7) = 1 ; f (0,3,4,5,7) = 1 ; f (1,2,4,5,8,12,13) = 1;

8. f (0,4,5,7) = 1 ; f (1,2,3,6,7) = 1 ; f (4,5,6,8,9,11,12) = 1;

9. f (0,1,2,3) = 1 ; f (3,4,5,6,7) = 1 ; f (8,9,11,12,13,14,15) = 1;

10. f (2,3,4,5) = 1 ; f (0,1,3,6,7) = 1 ; f (7,10,11,12,13,14,15) = 1;

11. f (3,4,5,6) = 1 ; f (0,1,2,5,7) = 1 ; f (0,4,8,12,13,14,15) = 1;

12. f (1,2,3,5) = 1 ; f (0,3,4,6,7) = 1 ; f (2,4,7,8,9,12,15) = 1;

13. f (1,2,3,6) = 1 ; f (0,2,4,5,7) = 1 ; f (3,6,9,12,13,14,15) = 1;

14. f (1,2,3,7) = 1 ; f (0,1,4,6,7) = 1 ; f (2,4,6,8,11,13,15) = 1;

15. f (1,2,4,6) = 1 ; f (0,1,4,5,7) = 1 ; f (0,5,7,10,11,12,13) = 1;

16. f (1,2,4,7) = 1 ; f (0,2,4,6,7) = 1 ; f (1,6,9,10,11,12,14) = 1;

17. f (0,1,3,6) = 1 ; f (1,2,4,5,6) = 1 ; f (0,2,4,9,11,12,13) = 1;

18. f (0,1,4,5) = 1 ; f (1,2,3,4,6) = 1 ; f (0,1,4,5,8,9,12) = 1;

19. f (0,1,3,5) = 1 ; f (1,2,4,6,7) = 1 ; f (1,2,4,15,9,10,12) = 1;

20. f (1,5,6,7) = 1 ; f (0,1,2,3,4) = 1 ; f (6,7,9,11,12,13,15) = 1;