Алмаев2
.pdf6.19.Проектирования на плоскость x + y = 0 .
6.20.Проектирования на плоскость x − z = 0 .
6.21.Зеркального отражения относительно плоскости x + z = 0 .
6.22.Поворота относительно оси Oz на угол π2 в положитель-
ном направлении.
6.23. Проектирования на плоскость 3y + z = 0 .
6.24.Зеркального отражения относительно плоскости Oxz .
6.25.Поворота относительно оси Oy на угол π2 в положитель-
ном направлении.
6.26. Проектирования на плоскость x + z = 0 . |
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6.27. Проектирования на плоскость y + 3z . |
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6.28. Проектирования на плоскость |
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6.29. Проектирования на плоскость |
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6.30. Поворота относительно оси Oz на угол |
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Задача 7. Найти собственные значения и собственные векторы
оператора, заданного матрицей |
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7.28. |
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Задача 8. Привести квадратичную форму к каноническому виду методом Лагранжа и записать соответствующее преобразование
8.1.x12 + 4x1 x2 + 4x1 x3 + 4x2 x3 + 4x32 .
8.2.4x12 + 4x1 x2 +8x1 x3 −3x22 + 4x32 .
8.3.4x12 +8x1 x2 + 4x1 x3 + x32 .
8.4.4x12 +8x1 x2 + 4x1 x3 +3x22 − 4x32 .
8.5.x12 + 4x1 x2 + 4x1 x3 +3x22 + 4x2 x3 + x32 .
8.6.x12 + 4x1 x2 + 4x2 x3 + x32 .
8.7.x12 + 2x1 x2 + 2x1 x3 −3x22 −6x2 x3 − 2x32 .
8.8.x12 + 4x1 x2 + 2x1 x3 +3x22 + 2x2 x3 + x32 .
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8.9.x12 + 4x1x3 − x22 −2x2 x3 + 4x32 .
8.10.x12 + 2x1x2 + 2x1 x3 + x32 .
8.11.x12 + 4x1x2 + 4x1 x3 +8x22 +12x2 x3 + 4x32 .
8.12.4x12 + 4x1x2 +8x1x3 +5x22 +8x2 x3 + 4x32 .
8.13.4x12 +8x1x2 + 4x1x3 +8x22 +8x2 x3 + x32 .
8.14.4x12 +5x22 + 4x32 +8x1 x2 + 4x1 x3 +8x2 x3 .
8.15.x12 + 4x1x2 + 4x1 x3 +5x22 +12x2 x3 +7x32 .
8.16.x12 + 4x1x2 + 4x1 x3 +8x22 +16x2 x3 +7x32 .
8.17.x12 + 2x1x2 + 2x1 x3 +5x22 +10x2 x3 + 4x32 .
8.18.x12 + 4x1x2 + 2x1 x3 +5x22 +6x2 x3 + x32 .
8.19.x12 + 4x1x3 + x22 + 2x2 x3 + 4x32 .
8.20.x12 + 2x1x2 + 2x1 x3 + 2x22 + 4x2 x3 + x32 .
8.21.x12 + 4x1x2 + 4x1 x3 + 4x2 x3 + 2x32 .
8.22.4x12 + 4x1x2 + 4x1 x3 −3x22 + 2x32 .
8.23.4x12 +8x1x2 + 4x1 x3 + x32 .
8.24.4x12 +8x1x2 + 4x1 x3 +3x22 − 4x32 .
8.25.x12 + 4x1x2 + 4x1 x3 +3x22 + 4x2 x3 − x32 .
8.26.x12 + 4x1x2 + 4x1 x3 − x32 .
8.27.x12 + 2x1x2 + 2x1 x3 −3x22 −6x2 x3 − 4x32 .
8.28.x12 + 4x1x2 + 2x1 x3 +3x22 + 2x2 x3 − x32 .
8.29.x12 + 4x1x3 − x22 −2x2 x3 + 2x32 .
8.30.x12 + 2x1x2 + 2x1 x3 − x32 .
Задача 9. Привести квадратичную форму к каноническому виду ортогональным преобразованием и записать соответствующее преобразование
9.1. 4x22 −3x32 −4x1x2 −4x1 x3 +8x2 x3 .
9.2. |
4x 2 |
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9.4.2x12 +9x22 + 2x32 −4x1x2 + 4x2 x3 .
9.5.−4x12 − 4x22 + 2x32 −4x1x2 +8x1 x3 −8x2 x3 .
9.6. |
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9.7. 4x |
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9.9.−x12 − x22 −3x32 − 2x1x2 −6x1 x3 + 6x2 x3 .
9.10.x12 −7x22 + x32 − 4x1 x2 −2x1 x3 − 4x2 x3 ;
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9.12. 3x |
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9.13. x 2 |
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9.14. x 2 |
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9.15. −2x |
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9.16.−(1 2)x12 +5x22 −(1 2)x32 − 4x1 x2 +3x1 x3 + 4x2 x3 .
9.17.x12 + x22 − x32 − 4x1 x3 + 4x2 x3 .
9.18.−2x12 + 2x22 − 2x32 + 4x1 x2 −6x1 x3 + 4x2 x3 .
9.19. |
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9.20. −4x |
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9.21. 10x 2 +14x 2 + 7x |
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9.23. |
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9.24. |
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9.25. |
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9.26. x 2 |
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9.27. 5x |
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9.28. |
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9.29. |
5x 2 |
+ 4x |
2 + 2x 2 |
−4x x |
− 2 |
2x x |
+ 4 2x x . |
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3 |
9.30. −2x12 +5x22 − 2x32 + 4x1 x2 + 4x2 x3 .
Задача 10. Исследовать кривую второго порядка и построить ее
10.1.−x2 − y2 + 4xy + 2x − 4 y +1 = 0;
10.2.2x2 + 2 y2 − 2xy − 2x − 2 y +1 = 0;
10.3.4xy + 4x − 4 y = 0;
10.4.−2x2 −2 y2 + 2xy −6x +6 y +3 = 0;
10.5.−3x2 −3y2 + 4xy −6x + 4 y + 2 = 0;
10.6.−2xy − 2x − 2 y +1 = 0;
10.7.−x2 − y2 − 4xy − 4x −2 y + 2 = 0;
10.8.−4x2 −4 y2 + 2xy +10x −10 y +1 = 0;
10.9.4xy + 4x − 4 y − 2 = 0;
10.10.x2 + y2 + 2xy −8x −8y +1 = 0;
10.11.x2 + y2 + 4xy −8x −4 y +1 = 0;
10.12.x2 + y2 − 2xy − 2x + 2 y −7 = 0;
10.13.2xy + 2x + 2 y −3 = 0;
10.14.4x2 + 4 y2 + 2xy +12x +12 y +1 = 0;
10.15.3x2 +3y2 + 4xy +8x +12 y +1 = 0;
10.16.x2 + y2 −8xy − 20x + 20 y +1 = 0;
10.17.3x2 +3y2 − 2xy −6x + 2 y +1 = 0;
10.18.4xy + 4x + 4 y +1 = 0;
10.19.3x2 +3y2 − 4xy + 6x − 4 y −7 = 0;
10.20.−4xy − 4x + 4 y + 6 = 0;
10.21.5x2 +5y2 − 2xy +10x −2 y +1 = 0;
10.22.2x2 + 2 y2 + 4xy +8x +8y +1 = 0;
10.23.−x2 − y2 + 2xy + 2x −2 y +1 = 0;
55
10.24.2x2 + 2 y2 −4xy −8x +8y +1 = 0;
10.25.3x2 +3y2 + 2xy −12x − 4 y +1 = 0;
10.26.−4xy +8x +8y +1 = 0;
10.27.2x2 + 2 y2 −2xy +6x −6 y −6 = 0;
10.28.x2 + y2 + 4xy + 4x + 2 y −5 = 0;
10.29.4xy + 4x −4 y + 4 = 0;
10.30.3x2 +3y2 − 4xy + 4x + 4 y +1 = 0 .
Задача 11. Ортогонализировать систему векторов e ,eG |
,eG |
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11.1. eG1 = (2,1, −1,0), 11.2. eG1 = (1,1, −1, −1), |
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1 |
2 |
3 |
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11.3. eG1 = (3,1, −1,1), |
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eG2 |
= (2, −1,2,1), |
e2 |
= (−4, −5,6,0), |
e2 |
= (−10, −4,5,0), |
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eG3 =(3,0,1,1). |
eG3 = (−3, −3,4,1). |
eG3 = (−6, −3,4,0). |
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11.4. eG1 = (2,2,3,1), |
11.5. eG1 = (1, −4, −3,1), 11.6. eG1 = (3, −10, −6,0), |
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eG2 |
= (1, −1,0,2), |
e2 |
= (1, −5, −3,0), |
e2 |
= (1, −4, −3,1), |
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eG3 =(−1,2,1,1). |
eG3 =(−1,6,4, −1). |
eG3 =(−1,5,4, −1). |
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11.7. eG1 = (1,0,0,2), |
11.8. eG1 = (1,0,0,3), |
11.9. eG1 = (1,0,0,3), |
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eG2 |
= (2,1,0,3), |
e2 |
= (−2,1,0,2), |
e2 |
= (11,0,2), |
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eG3 |
=(−3,2,1,1). |
eG3 |
= (7, −2,1,0). |
eG3 |
= (−2,0,1,2). |
11.10. eG1 |
= (1,2, −3,1), 11.11. eG1 = (1, −2,7,0), 11.12. eG1 = (2,6,5,0), |
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eG2 = (0,1,2,3), |
e2 |
= (0,1, −2,2), |
e2 |
= (5,3, −2,1), |
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eG3 =(0,0,1,5). |
eG3 = (0,0,1,4). |
eG3 = (7,4, −3,0). |
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11.13. eG1 |
= (2,5,7,0), 11.14. eG1 = (3,2,3,1), 11.15. eG1 = (3, −4,5,0), |
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eG2 |
= (6,3,4,1), |
e2 |
= (−4, −3,−5,0), |
e2 |
= (2, −3,1,2), |
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eG3 |
= (5, −2, −3,1). |
eG3 = (5,1, −1,2). |
eG3 = (3, −5, −1,1). |
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11.16. eG1 |
= (1,0,1,2), |
11.17. eG1 = (−1,1, −1,3), |
11.18. eG1 = (2,0,1,3), |
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eG2 |
= (2,1,1,2), |
e2 |
= (0,0,1,4), |
e2 |
= (0,1,0,2), |
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eG3 |
= (0,1,0,3). |
eG3 |
= (2, −1,1,2). |
eG3 |
=(−1,0,0,4). |
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11.19. eG1 = (1,2,0,2), |
11.20. eG1 = (−1,0,2,3), 11.21. eG1 = (2,0, −1,1), |
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eG2 = (0,1,1,3), |
e2 |
= (1,0, −1,2), |
e2 = (0,1,0,3), |
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eG3 = (1,1,0, 2). |
eG3 =(−1,1,1,1). |
eG3 =(1,0,0,3). |
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11.22. eG1 = (2,3,5,0), |
11.23. eG1 = (0,0,1,3), |
11.24. eG1 = (2,0,1,2), |
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eG2 = (0,1,2,2), |
e2 |
= (2, −5, −4,0), |
e2 =(3,1,0,1), |
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eG3 = (1,0,0,3). |
eG3 =(−1,3,2,1). |
eG3 = (5,2,0,1). |
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11.25. eG1 = (0,2, −1,2), 11.26. eG1 = (−3, −1, −9,0), 11.27. eG1 = (2,2,3,1), |
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eG2 |
= (0,5,3,1), |
e2 |
=(0, −2,1,1), |
e2 |
= (1, −1,0,2), |
eG3 |
= (1, −4,2,1). |
eG3 = (1,2,2,1). |
eG3 |
=(−1,2,1,1). |
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11.28. eG1 = (2,1,3,1), 11.29. eG1 = (1, −4, −3,1), 1.30. eG1 = (3, −10, −6,0), |
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eG2 |
= (0,1,2,3), |
e2 |
=(2, −5, −3,0), |
e2 |
= (1, −4, −3,1), |
eG3 |
=(0,3,1,5). |
eG3 = (−1,6,4,1). |
eG3 |
=(−2,5,4, −1). |
Задача 12. Найти проекцию вектора xG на подпространство, по- |
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рожденное векторами |
a , aG |
, aG , и ортогональную составляющую |
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вектора xG |
1 |
2 |
3 |
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12.2. aG1 = (3,0,2,2), |
12.3. aG1 = (−1,5,1,1), |
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12.1. aG1 = (1,1,1,1), |
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aG2 |
= (2, −1,1,1), |
a2 |
= (1, −2,0,0), |
a2 |
= (0,3,1,1), |
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aG3 |
= (2, −7, −1, −1), |
aG3 = (03,1,1), |
aG3 |
= (1,1,1,1), |
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xG = (−3,5,9,3). |
xG =(−3,5,9,3). |
xG =(4, −4, −8, −4). |
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12.4. aG1 = (4, −5,1,1), |
12.5. aG1 = (1, −5, −1, −1), |
12.6. aG1 = (0,3,1,1), |
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aG2 |
= (3,0,2,2), |
a2 |
= (2,5,3,3), |
a2 |
= (1, −5, −1, −1), |
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aG3 |
= (1, −2,0,0), |
aG3 |
= (3,0,2,2), |
aG3 |
= (2,5,3,3), |
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xG = (2, −6, −10,−4). |
xG = (3, −5, −9, −3). |
xG = (−4,4,8,4). |
57
12.7. aG1 = (2, −1,1,1), |
12.8. aG1 = (1, −14, −4, −4), 12.9. aG1 = (3,0,2,2), |
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aG2 |
= (4, −5,1,1), |
a2 |
= (1, −2,0,0), |
a2 |
= (1, −14, −4, −4), |
aG3 |
= (−1,5,1,1), |
aG3 |
= (1,1,1,1), |
aG3 |
= (0,3,1,1), |
xG = (−2,6,10,4). |
xG = (−4,1,7,1). |
xG = (−5,0,6.0). |
12.10. aG1 =(1, −2,0,0), 12.11. aG1 =(1,10,4,4), 12.12. aG1 =(2, −7, −1, −1), |
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aG2 |
= (2, −7, −1,1), |
a2 = (1,1,1,1), |
a2 = (4,1,3,3), |
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aG3 = (1, −14, −4, −4), |
aG3 = (4,1,3,3), |
aG3 = (2, −1,1,1), |
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xG = (4, −1, −7, −1). |
xG = (3, −2, −8, −2). |
xG = (−1,7,11,5). |
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12.13. aG1 = (2, −1,1,1), |
2.14. aG1 = (3,0,2,2), |
12.15. aG1 = (2, −1,1,1), |
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aG2 = (1,10,4,4), |
a2 |
= (−1,14,4,4), |
a2 |
= (2, −7, −1, −1), |
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aG3 |
= (4, −5,1,1), |
aG3 |
=(1,10,4,4), |
aG3 |
= (1,1,1,1), |
xG = (−3,2,8,2). |
xG = (−3,5,9,3). |
xG = (1, −1, −2,−1). |
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12.16. aG1 = (1, −2,0,0), |
12.17. aG1 = (0,3,1,1), |
12.18. aG1 = (3,0,2,2), |
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aG2 |
= (0,3,1,1), |
a2 |
= (1,1,1,1), |
a2 |
= (4, −5,1,1), |
aG3 |
= (3,0,2,2), |
aG3 |
= (−1,5,1,1), |
aG3 |
= (1, −2,0,0), |
xG = (1, −3, −5,−2). |
xG = (2, −2, −4, −2). |
xG = (3, −5, −9, −3). |
12.19. aG1 = (2,5,3,3), 12.20. aG1 = (4, −5,1,1), 12.21. aG1 = (−1,2,0,0), |
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aG2 |
= (3,0,2,2), |
a2 |
=(−1,5,1,1), |
aG2 |
= (1,11,1), |
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aG3 |
= (1, −5, −1, −1), |
aG3 |
= (2, −1,1,1), |
aG3 |
=(−1,14,4,4), |
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xG = (−1,1,2,1). |
xG =(−1,3,5,2). |
xG = (5,0, −6,0). |
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12.22. aG1 = (−2,7,1,1), |
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12.23. aG1 = (1,1,1,1), |
12.24. aG1 = (4,1,3,3), |
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aG2 |
= (1, −14,−4,−4), |
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a2 |
= (4,1,3,3), |
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a2 |
= (2, −11,1), |
aG3 |
= (1, −2,0,0), |
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aG3 |
= (1,10,4,4), |
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aG3 |
= (−2,7,1,1), |
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xG = (−4,1,7,1). |
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xG = (4, −1, −7, −1). |
xG = (3, −2, −8, −2). |
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12.25. aG1 = (1,10,4,4), 12.26. aG1 = (−1,14,4,4), 2.27. aG1 = (−2,7,1,1), |
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aG2 = (1, −14, −4,−4), |
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a2 |
= (4, −5,1,1), |
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a2 = (1,10,4,4), |
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aG3 = (1, −2,0,0), |
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aG3 = (2, −1,1,1), |
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aG3 = (3,0,2,2), |
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xG = (−4,1,7,1). |
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xG = (−1,7,11,5). |
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xG = (−3,2,8,2). |
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12.28. aG1 = (4, −5,1,1), 12.29. aG1 = (1, −5, −1, −1), |
12.30. aG1 = (0,3,1,1), |
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aG2 = (3,0,2,2), |
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a2 = (2,5,3,3), |
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a2 = (1, −5, −1, −1), |
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aG3 = (1, −2,0,0), |
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aG3 = (3,0,2,2), |
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aG3 = (2,5,3,3), |
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xG = (2, −6, −10,−4). |
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xG = (3, −5, −9, −3). |
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xG = (−4,4,8,4). |
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Задача 13. Найти жорданову форму матрицы |
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13.1. |
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13.2. |
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13.3. |
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13.4. |
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13.5. |
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13.6. |
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13.7. |
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13.8. |
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13.10. |
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13.13. |
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13.14. |
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13.15. |
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13.16. |
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13.17. |
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13.19. |
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13.22. |
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13.23. |
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3.24. −5 |
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13.25. |
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13.26. |
|
0 |
|
2 |
0 |
|
13.27. |
|
−5 |
|
−7 |
−6 |
|
|
|||
|
|
|
|
|
|
|
|
|
|
|
|||||||||||||||
|
|
−1 −1 1 |
|
|
|
|
|
|
|
|
|
|
|
|
|
−6 |
|
−8 |
−7 |
|
|
||||
|
|
|
|
|
|
−1 0 −3 |
|
|
|
|
|
|
|
||||||||||||
|
|
3 0 8 |
|
|
−2 8 6 |
|
|
|
−2 1 2 |
|
|
||||||||||||||
13.28. |
|
3 |
−1 |
6 |
|
13.29. |
|
|
|
10 |
6 |
|
13.30. |
|
−1 |
0 |
2 |
|
|
|
|||||
|
|
−4 |
|
|
|
|
|
||||||||||||||||||
|
|
−2 0 −5 |
|
|
|
|
4 −8 |
−4 |
|
|
|
|
−2 0 3 |
|
|
|
|||||||||
|
|
|
|
|
|
|
|
|
|
|
|
|
60