ОКТ, Заочка, 1 курс 2 вариант
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Д) 62,88(10) = 111110,11100 (2);
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.88*2=1.76 |
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.76*2=1.52 |
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.52*2=1.04 |
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.04*2=0.08 |
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.08*2=0.16 |
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.16*2=0.32 |
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.32*2=0.64 |
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.64*2=1.28 |
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.28*2=0.56 |
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.56*2=1.12 |
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Из 10 в 8 (переводим по триадам)
А) 753(10) = 001011110001(2)=1361(8);
Б) 404(10) = 110010100(2)=624(8);
В) 111,1875(10) =001101111,001100(2)= 157,14(8);
Г) 907,0625(10) =001110001011,000100(2)= 1613,04(8);
Д) 62,88(10) = 111110,111000010100(2)=76,7024(8);
Из 10 в 16 (переводим по тетрадам)
А) 753(10) =001011110001(2) = 2F1(16);
Б) 404(10) =110010100(2)= 194(16);
В) 111,1875(10) =001101111,001100(2)= 6F,3(16);
Г) 907,0625(10) =001110001011,000100(2)= 38B,1(16);
Д) 62,88(10) =111110,111000010100(2)=3E,E14(16);
Задание 2
А) 11100011 (2) =1*20+1*21+1*25+1*26+1*27= 227(10);
Б) 1111001111(2) =1*20+1*21+1*22+1*23+1*26+1*27+1*28+1*29= 975(10);
В) 1011111111,01001(2) = 20+21+22+23+24+25+26+27+29, 2-2+2-5+=767,28(10);
Г) 1001011101,011(2) =20+22+23+24+26+29, 2-2+2-3= 605,375(10);
Д) 615,72(8) =(6*82)+(1*81)+(5*80),(7*8-1)+(2*8-2)= 397,90625(10);
Е) 3DA,5(16) (3*162)+(13*161)+(10*160),(5*16-1)= 986,3125(10);
Задание 3
А) 1100101011(2) + 1010110010(2) = 10111011101(2);
Б) 110100111(2) + 1100100010(2) = 10011001001(2);
В) 1100110100,0011(2) + 1101110000,01(2) = 11010100100,0111(2);
Г) 477,2(8) + 647,4(8) = 1346,6(8);
Д) 372,4(16) + 1F0,4(16) = 562,8(16);
Задание 4
А) 1001100000(2) - 111001000(2) = 10011000(2);
Б) 1100001110(2)-110000001(2) = 110001101(2);
В) 1100110100,01(2) - 101100010,101(2) = 111010001,101(2);
Г) 543,46(8) - 517,2(8) = 24,26(8);
Д) 284,B(16) - 77,4(16) = 20D,7(16);
Задание 5
А) 1100010(2) * 100001(2) = 110010100010(2);
Б) 1324,2(8) * 75,54(8) = 1272051,13(8);
В) 66,D(16) * 1C,D(16) = B92,49(16);
Задание 6
А) 1110110101(2) : 1101(2) = 1001001(2);
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Б) 5366(8) : 27(8) = 172(8);
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В) 76C(16) : 19(16) = 4C(16);
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