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060 Navigation 2 - Radio Navigation - 2014.pdf
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19 Revision Questions

Appendix A

Questions Revision 19

378

Answers 19

Answers to Specimen Examination Paper

 

1

2

3

4

5

6

7

8

9

10

11

12

 

b

c

d

a

a

d

b

c

a

c

d

d

 

 

 

 

 

 

 

 

 

 

 

 

 

13

14

15

16

17

18

19

20

21

22

23

24

 

c

a

d

a

d

b

a

b

c

d

b

d

 

 

 

 

 

 

 

 

 

 

 

 

 

25

26

27

28

29

30

31

32

33

34

35

36

 

a

d

b

c

b

a

a

a

b

c

a

d

 

 

 

 

 

 

 

 

 

 

 

 

 

37

38

39

40

41

42

43

44

45

46

47

48

 

d

b

a

b

b

d

b

b

c

a

d

a

 

 

 

 

 

 

 

 

 

 

 

 

 

49

50

51

52

53

54

55

56

57

58

59

60

 

c

c

b

d

b

a

a

a

a

c

d

b

 

 

 

 

 

 

 

 

 

 

 

 

 

61

62

63

64

65

66

 

 

 

 

 

 

 

b

c

b

a

b

b

 

 

 

 

 

 

Answers 19

379

Q27. Range =

19 Answers

Explanation of Selected Questions

Q1. Use c = λf

Q5. Line of sight formula: Range (NM) = 1.23 (√hTX + √hRX ) (height in feet)

Q13. Line of sight formula again! Maximum range at which reception can be achieved is 195 NM.

Q14. The phase difference is the bearing of the aircraft from the beacon (radial).

Q15/16. Draw a diagram!

Q18. Height = Glide path angle × range × 100 ft

Time interval

NM

2 × 6.17

Q36. The mode C increments in 100 ft steps.

Q37. 1262 MHz is outside the allocated band for DME.

Q39. Pythagoras!

Q54. The 50 Hz modulation passes the Nav and System Data message. The PRN codes provide a timing function and SV identification.

Q57. The range displayed is to the waypoint.

Q62. Remember the PLAN display is orientated to TRUE north.

Answers 19

380

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